Sum of First K Integers

The program must accept N integers and an integer K as the input. The program must find the sum of the first K integers as S. The program must consider the last K integers and for each integer X among the last K integers, the program must print difference between S and X as the output.

Boundary Condition(s):
1 <= N <= 10^5
1 <= K <= N

Input Format:
The first line contains the two integers N and K separated by a space.
The second line contains N integers separated by spaces.

Output Format:
The first line contains K integers separated by space(s).

Example Input/Output 1:
Input:
7 5
10 20 30 40 50 60 70

Output:
120 110 100 90 80

Explanation:
K = 5,
The first 5 integers are 10, 20, 30, 40 and 50 and their sum is 150 (10 + 20 + 30 + 40 + 50).
The last 5 integers are 30, 40, 50, 60 and 70.
For integer 30, the difference between 150 and 30 is 120 (150-30). So 120 is printed.
For integer 40, the difference between 150 and 40 is 110 (150-40). So 110 is printed.
For integer 50, the difference between 150 and 50 is 100 (150-50). So 100 is printed.
For integer 60, the difference between 150 and 60 is 90 (150-60). So 90 is printed.
For integer 70, the difference between 150 and 70 is 80 (150-70). So 80 is printed.

Example Input/Output 2:
Input:
4 2
10 5 12 20 

Output:
3 -5

Solution:-

#include<stdio.h>

#include <stdlib.h>

int main()

{

    int n,k;

    scanf("%d %d",&n,&k);

    

    int arr[n];

    

    for(int i=0;i<n;i++)

    {

        scanf("%d ",&arr[i]);

    }

    

    int sum=0;

    

    for(int i=0;i<k;i++)

    {

        sum=sum+arr[i];

    }

    

    for(int i=n-k;i<n;i++)

    {

        printf("%d ",sum-arr[i]);

    }

    

}