Alphabets Positions Reversed

The program must accept N alphabets as the input. The program must print the alphabet position of each alphabet in reverse order as the output.

Boundary Condition(s):
1 <= N <= 10^5

Input Format:
The first line contains the integer N.
The second line contains N characters separated by space(s).

Output Format:
The first line contains the alphabet position of N alphabets in the reverse order.

Example Input/Output 1:
Input:
5
j a e E b

Output:
2 5 5 1 10

Explanation:
The alphabet position of j is 10 in the alphabetical order.
The alphabet position of a is 1 in the alphabetical order.
The alphabet position of e is 5 in the alphabetical order.
The alphabet position of E is 5 in the alphabetical order.
The alphabet position of b is 2 in the alphabetical order.
In the reverse order, the alphabets position are 2 5 5 1 10
Hence the output is 2 5 5 1 10

Example Input/Output 2:
Input:
4
L f V d

Output:
4 22 6 12 

Solution:-

#include<stdio.h>

#include <stdlib.h>

int main()

{

    int n,x=0;

    scanf("%d",&n);

    char arr[n];

    char a;

    

    for(int i=0;i<n;i++)

    {

        scanf(" %c",&arr[i]);

        

    }

    

    

    for(int i=n-1;i>=0;i--)

    {

        if(isupper(arr[i]))

        printf("%d ",arr[i]-'A'+1);

        else

        printf("%d ",arr[i]-'a'+1);

    }

    

}